Calcular la masa molecular de los siguientes compuestos a) H3BO3 b) AL2(SO4)3 c) H3PO3 d) H2CO3 e) HNO3 f) C6H1206 Doy 20 puntos pero aurita Por favor es urgente que p * * * * van a responder.
En resumen
Respuesta : H3BO3 H : 3 x 1 = 3 g / mol B : 1 X 10. 8 = 10. 8 g / mol O : 3 x 16 = 48 g / mol ``````````````````` ````````````` Mm = 61.
Respuesta : H3BO3
H : 3 x 1 = 3 g / mol
B : 1 X 10.
8 = 10.
8 g / mol
O : 3 x 16 = 48 g / mol
``````````````````` ````````````` Mm = 61.
8 g / mol
H2CO3
H : 2x 1 = 2 g / mol
C : 1 X 12 = 12 g / mol
O : 3 x 16 = 48 g / mol
``````````````````` ````````````` Mm = 62 g / mol
AL2(SO4)3
Al : 2 x 27 = 54 g / mol
S : 3 x 32 = 96 g / mol
O : 12 x 16 = 192 g / mol
```````````````````````````````` Mm = 342 g / mol
H3PO3
H : 3 x 1 = 3 g / mol
P : 1 x 31 = 31 g / mol
O : 3 x 16 = 48 g / mol
```````````````````````````````` Mm = 82 g / mol
HNO3
H : 1 x1 = 1 g / mol
N : 1 x 14 = 14 g / mol
O : 3 x 16 = 48 g / mol
`````````````````````````````` Mm = 63 g / mol
C6H12O6
C : 6 x 12 = 72 g / mol
H : 12 x 1 = 12 g / mol
O : 6 x 16 = 96 g / mol
`````````````````````````````````` Mm = 180 g / mol
Explicación : H3BO3
H : 3 x 1 = 3 g / mol
B : 1 X 10.
8 = 10.
8 g / mol
O : 3 x 16 = 48 g / mol
``````````````````` ````````````` Mm = 61.
8 g / mol
H2CO3
H : 2x 1 = 2 g / mol
C : 1 X 12 = 12 g / mol
O : 3 x 16 = 48 g / mol
``````````````````` ````````````` Mm = 62 g / mol
AL2(SO4)3
Al : 2 x 27 = 54 g / mol
S : 3 x 32 = 96 g / mol
O : 12 x 16 = 192 g / mol
```````````````````````````````` Mm = 342 g / mol
H3PO3
H : 3 x 1 = 3 g / mol
P : 1 x 31 = 31 g / mol
O : 3 x 16 = 48 g / mol
```````````````````````````````` Mm = 82 g / mol
HNO3
H : 1 x1 = 1 g / mol
N : 1 x 14 = 14 g / mol
O : 3 x 16 = 48 g / mol
`````````````````````````````` Mm = 63 g / mol
C6H12O6
C : 6 x 12 = 72 g / mol
H : 12 x 1 = 12 g / mol
O : 6 x 16 = 96 g / mol
`````````````````````````````````` Mm = 180 g / mol.
H3BO3
H : 3 x 1 = 3 g / mol
B : 1 X 10.
8 = 10.
8 g / mol
O : 3 x 16 = 48 g / mol
``````````````````` ````````````` Mm = 61.
8 g / mol
H2CO3
H : 2x 1 = 2 g / mol
C : 1 X 12 = 12 g / mol
O : 3 x 16 = 48 g / mol
``````````````````` ````````````` Mm = 62 g / mol
AL2(SO4)3
Al : 2 x 27 = 54 g / mol
S : 3 x 32 = 96 g / mol
O : 12 x 16 = 192 g / mol
```````````````````````````````` Mm = 342 g / mol
H3PO3
H : 3 x 1 = 3 g / mol
P : 1 x 31 = 31 g / mol
O : 3 x 16 = 48 g / mol
```````````````````````````````` Mm = 82 g / mol
HNO3
H : 1 x1 = 1 g / mol
N : 1 x 14 = 14 g / mol
O : 3 x 16 = 48 g / mol
`````````````````````````````` Mm = 63 g / mol
C6H12O6
C : 6 x 12 = 72 g / mol
H : 12 x 1 = 12 g / mol
O : 6 x 16 = 96 g / mol
`````````````````````````````````` Mm = 180 g / mol.
COMO SON LOS COMPUESTOS QUIMICOS EJERCICIOS.
A) Fe : 56 * 2 = 112 C : 12 * 3 = 36 O : 16 * 3 * 3 = 144 suma : 292g peso molecular del compuesto, 292 g / mol b) C : 12 * 6 = 72 H : 1 * 12 = 12 O : 16 * 6 = 96 suma : 180g peso molecular del compuesto : 180g / mol.
Ya mira bro es super sencillo el 78 g / mol lo formulas en una ecuacion como tiene carbono (c) = 12 ; hidrogeno (h) = 1 haces lo siguiente 78 = (12 + 1)n n es una valor que agregas para poder sumar la masa molecular de…
FE = CH Mm = 78 g / mol Mm CH C : 1 x 12 = 12 g / mol H : 1 x 1 = 1 g / mol ```````````````````````````` Mm = 13 g / mol n = 78 g / mol `````````````` 13 g / mol n = 6 FM = (CH)₆ = C₆H₆ (BENCENO).