Calcula al masa de hidróxido de calcio Ca(OH)2, necesaria para reaccionar con 16, 5 g de ácido clorhídrico, HCl?
Calcula al masa de hidróxido de calcio Ca(OH)2, necesaria para reaccionar con 16, 5 g de ácido clorhídrico, HCl.
En resumen
Ca(OH)2 + 2HCl → CaCl2 + 2H2O Mm Ca(OH)2 = 74 g / mol HCl = 36. 4 g / mol g Ca(OH)2 = 16. 5 g HCl x 1 mol HCl x 1 mol Ca(OH)2 x 74 g Ca(OH)2 `````````````` `````````````````````` ``````````````````` 36. 4 g HCl 2 mol HCl 1 mol Ca(OH)2 g = 16. 77 g de Ca(OH)2.
Mejor respuesta
4
Ca(OH)2 + 2HCl → CaCl2 + 2H2O
Mm Ca(OH)2 = 74 g / mol HCl = 36.
4 g / mol
g Ca(OH)2 = 16.
5 g HCl x 1 mol HCl x 1 mol Ca(OH)2 x 74 g Ca(OH)2 `````````````` `````````````````````` ``````````````````` 36.
4 g HCl 2 mol HCl 1 mol Ca(OH)2
g = 16.
77 g de Ca(OH)2.