Balencear por metodo de redox la siguente ecuacion NH3 + O2 - - - - - - - > NO + H2O ,Fe + H2O - - - - - - > Fe3O4 + H2?

<img src="https://tex.z-dn.net/?f=%5C%5CNH_3%2BO_2--%3ENO%2BH_2O%5C%5C%0A%5C%5C%0AN%5E-%5EI%5EI%5EI%20-5e--%3EN%5EI%5EI%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%2F%5Ccdot%204%5C%5C%0AO_2%5E0%20%2B4e--%3E2O%5E-%5EI%5EI%5C%20%5C%20%5C%20%5C%20%5C%20%2F%5Ccdot%205%5C%5C%0A%5C%5C%0A4NH_3%2B5O_2--%3E4NO%2B6H_2O" />NO + H_2O \ \ &#10 ; \ \ &#10 ; N ^ - ^ I ^ I ^ I - 5e - - >N ^ I ^ I \ \ \ \ \ \ / \ cdot 4 \ \ &#10 ; O_2 ^ 0 + 4e - - >2O ^ - ^ I ^ I \ \ \ \ \ / \ cdot 5 \ \ &#10 ; \ \ &#10 ; 4NH_3 + 5O_2 - - >4NO + 6H_2O" alt = " \ \ NH_3 + O_2 - - >NO + H_2O \ \ &#10 ; \ \ &#10 ; N ^ - ^ I ^ I ^ I - 5e - - >N ^ I ^ I \ \ \ \ \ \ / \ cdot 4 \ \ &#10 ; O_2 ^ 0 + 4e - - >2O ^ - ^ I ^ I \ \ \ \ \ / \ cdot 5 \ \ &#10 ; \ \ &#10 ; 4NH_3 + 5O_2 - - >4NO + 6H_2O" align = "absmiddle" class = "latex - formula">

<img src="https://tex.z-dn.net/?f=%5C%5CFe%2BH_2O--%3EFe_3O_4%2BH_2%5C%5C%0A%5C%5C%0A3Fe%5E0%20-%208e%20--%3E3Fe%5EI%5EI%5E%7C%5EI%5EI%5EI%5C%5C%0A2H%5EI%20%2B%202e%20--%3EH_2%5E0%5C%20%5C%20%5C%20%5C%20%5C%20%2F%5Ccdot%204%5C%5C%0A%5C%5C%0A3Fe%2B4H_2O--%3EFe_3O_4%2B4H_2" />Fe_3O_4 + H_2 \ \ &#10 ; \ \ &#10 ; 3Fe ^ 0 - 8e - - >3Fe ^ I ^ I ^ | ^ I ^ I ^ I \ \ &#10 ; 2H ^ I + 2e - - >H_2 ^ 0 \ \ \ \ \ / \ cdot 4 \ \ &#10 ; \ \ &#10 ; 3Fe + 4H_2O - - >Fe_3O_4 + 4H_2" alt = " \ \ Fe + H_2O - - >Fe_3O_4 + H_2 \ \ &#10 ; \ \ &#10 ; 3Fe ^ 0 - 8e - - >3Fe ^ I ^ I ^ | ^ I ^ I ^ I \ \ &#10 ; 2H ^ I + 2e - - >H_2 ^ 0 \ \ \ \ \ / \ cdot 4 \ \ &#10 ; \ \ &#10 ; 3Fe + 4H_2O - - >Fe_3O_4 + 4H_2" align = "absmiddle" class = "latex - formula">.