Balancear por el Metodo de redox ;Pb + AgNO3 = Pb(NO3)2 + AgyCobre + oxigeno = oxido cuprico?

<img src="https://tex.z-dn.net/?f=%5C%5CPb%2BAgNO_3--%3EPb%28NO_3%29_2%2BAg%5C%5C%20%5C%5C%20Pb%5E0-2e--%3EPb%5EI%5EI%5C%5C%20Ag%5EI%2Be--%3EAg%5E0%5C%20%5C%20%5C%20%5C%20%5C%20%2F%5Ccdot%202%5C%5C%20%5C%5C%20Pb%2B2AgNO_3--%3EPb%28NO_3%29_2%2B2Ag" />Pb(NO_3)_2 + Ag \ \ \ \ Pb ^ 0 - 2e - - >Pb ^ I ^ I \ \ Ag ^ I + e - - >Ag ^ 0 \ \ \ \ \ / \ cdot 2 \ \ \ \ Pb + 2AgNO_3 - - >Pb(NO_3)_2 + 2Ag" alt = " \ \ Pb + AgNO_3 - - >Pb(NO_3)_2 + Ag \ \ \ \ Pb ^ 0 - 2e - - >Pb ^ I ^ I \ \ Ag ^ I + e - - >Ag ^ 0 \ \ \ \ \ / \ cdot 2 \ \ \ \ Pb + 2AgNO_3 - - >Pb(NO_3)_2 + 2Ag" align = "absmiddle" class = "latex - formula">

<img src="https://tex.z-dn.net/?f=%5C%5CCu%2BO_2--%3ECuO%5C%5C%20%5C%5C%20Cu%5E0-2e--%3ECu%5EI%5EI%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%2F%5Ccdot%202%5C%5C%20O_2%5E0%2B4e--%3E2O%5E-%5EI%5EI%5C%5C%20%5C%5C%202Cu%2BO_2--%3E2CuO" />CuO \ \ \ \ Cu ^ 0 - 2e - - >Cu ^ I ^ I \ \ \ \ \ \ \ / \ cdot 2 \ \ O_2 ^ 0 + 4e - - >2O ^ - ^ I ^ I \ \ \ \ 2Cu + O_2 - - >2CuO" alt = " \ \ Cu + O_2 - - >CuO \ \ \ \ Cu ^ 0 - 2e - - >Cu ^ I ^ I \ \ \ \ \ \ \ / \ cdot 2 \ \ O_2 ^ 0 + 4e - - >2O ^ - ^ I ^ I \ \ \ \ 2Cu + O_2 - - >2CuO" align = "absmiddle" class = "latex - formula">.