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12. Mm NH3 = 17 g / mol HCl = 36.

45 g / mol Cs2O = 281.

8 g / mol

1.

Calcular moles de cada componente : (n = masa / Mm)

n NH3 = 43 g / 17 g / mol = 2.

53 mol

n Cs2O = 25 g / 281.

8 g / mol = 0.

089 mol

n HCl = 87 g / 36.

45 g / mol = 2.

38 tg / mol

2.

Calcular moles totales : n = nNH3 + n Cs2O + nHCl

n totales = 2.

53 moles + 0.

089 moles + 2.

38 moles

n totales = 4.

999 moles ≈ 5 moles

3.

Calcular fraccion molar de cada componente

X NH3 = 2.

53 moles / 5 moles = 0.

506

XCs2O = 0.

089 moles / 5 moles = 0.

0178 moles

XHCl = 2.

38 moles / 5 moles = 0.

476

13.

Mm NH3 = 17 g / mol N2 = 28 g / mol

Fracción molar :

n totales = 1

moles NH3 = sustancia a

moles N2 = sustancia b entonces :

Xa = na / nt ; Xb = nb / nt

ahora sustutuir :

moles NH3 = 0.

17 x 1 = mol = 0.

17 mol (a)

moles N2 = 0.

83 x 1 mol = 0.

83 mol (b)

se debe calcular la masa de cada sustancia aplicando la fórmula :

n = masa / Mm

mNH3 = nNH3 x Mm (sustancia a)

mn2 = nN2 x Mm ( sustancia b)

donde m Total = mNH3 + mN2 ( masa solución)

se calcula el % de cada sustancia aplicando la

%m / m = masa soluto x 100 `````````````````` m solc.

%m / m (a) = ma (mNH3) x 100 `````````````````` masa total

%m / m (b) = m b (mN2) x 100 ``````````````` masa total.