QuímicaBásico1 respuestas

Ayuda necesito resolver estooop?

Ayuda necesito resolver estooop.

En resumen

18 - Mm CH4 = 16 g / mol n(moles) = masa / Mm n = 0. 25 masa = 0. 25 x 16 g / mol = 4 g 19. N = 0. 125 moles Mm Na2HPO4 = 142 g / mol m = 0. 125 moles x 142 g / mol = 17. 75 g 20. Mm agua = 18 g / mol m = 18 g / mol x 0. 23 mol = 4. 14 g 21. MmH2SO4 = 98 g / mol m = 32.

Mejor respuesta

Becky00zen
10

18 - Mm CH4 = 16 g / mol

n(moles) = masa / Mm

n = 0.

25

masa = 0.

25 x 16 g / mol = 4 g

19.

N = 0.

125 moles

Mm Na2HPO4 = 142 g / mol

m = 0.

125 moles x 142 g / mol = 17.

75 g

20.

Mm agua = 18 g / mol

m = 18 g / mol x 0.

23 mol = 4.

14 g

21.

MmH2SO4 = 98 g / mol

m = 32.

5 moles x 98 g / mol = 3185 g

22.

Mm butano = 58 g / mol

m = 50 g

n = 50 g / 58 g / mol = 0.

862 moles de butano

23.

Mm H2CO3 = 62 g / mol

n = 62 g / 62 g / mol = 1 mol

24.

Mm Na2SO4 = 142 g / mol

moles (n) = 142 g / 142 g / mol = 1 mol

25.

Mm KHCO3 = 100 g / mol

n = 10 g / 100 g / mol = 0.

1 mol

29.

Mm NaOH = 40 g / mol

moles = 1 g / 40 g / mol = 0.

025 moles de NaOH

31.

Mm SO2 = 64 g / mol

g = 1 x 10²¹ moléculas x 64 g `````````` 6.

022 x 10²³ moleculas

g = 0.

106

33.

Mm H2O = 18 g / mol

g = 1 molécula x 18 g ```````````` 6.

022 x ²³ moléculas

g = 2.

98 x ²³

34.

Mm O2 = 32 g / mol

g = 1 molecula de O2 x 32 g O2 `````````````````` 6.

022 x ²³ moleculas

g = 5.

31 x 10⁻²³

35.

Mm C12H22O11 = 342 g / mol

g = 1 molecula x 342 g ```````````````````` 6.

022 x 10²³ moléculas

g = 5.

68 x 10⁻²²

37.

Mm NaOH = 40 g / mol

particulas = 1 g x 6.

022 x 10²³ particulas `````````````````````````````````` 39.

99 g

particulas = 1.

50 x 10 ²².