Ayuda con el a, por favor?

A. Zn + 2HCl → ZnCl2 + H2↑

b.

Mm Zn = 65.

39 g / mol

calcular moles de Zn aplicando la fórmula n = masa / Mm

n = 60 g / 65.

39 g / mol

n = 0.

918 moles Zn

calcular Volumen de HCl

V HCl = 0.

918 mol Zn x 2 mol HCl x 1 L HCl ```````````````` `````````````` 1 mol Zn 3 mol HCl

V HCl = 0.

612 Litros

V HCl = 0.

612 x 1000 = 612 mL

B.

Calcular V de hidrógeno

1.

Calcular moles de H2

mol H2 = 0.

918 mol Zn x 1 mol H2 `````````````` 1 mol Zn

mol H2 = 0.

918

2.

Aplicar Ley general de los Gases

V · P = n · R · T

P = 1 atm

n = 0.

918 mol H2

T = 298 K

R = 0.

082 (L atm / mol K )

V = 0.

918 moles · 0.

082 (L atm / mol K) · 298 K `````````````````````````````````````````````````````````````` 1 atm

V = 22.

43 Litros

d) Zn + 2HCl → ZnCl2 + H2

(65.

39 g) + 2(36.

45 g)→ (136.

29 g) + (2 g) 65.

39 g + 72.

9 g = 136.

29 g + 2 g 138.

29 g = 138.

29 g

se cumple la ley de la conservación de la masa.