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AYUDA?

AYUDA! Tengo que sacar el peso molecular de estos compuestos : - Al2 SO3 - K2O - Na2o - CaSO4 - PbCl2 - Li2O - NaOH - FeO - Fe2O3 - Mn2O7 - Hg2O - Al2O3 - V2O5 - MgO - CuO - PlO2 - OCdO PORFAVOR!

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Sebastiansanzbr
9

Al2 (SO3)3

Al : 2 x 27 = 54 g / mol

S : 3 x 32 = 96 g / mol

O : 9 x 16 = 144 g / mol

```````````````````````````` Mm = 297 g / mol - K2O

K : 2 x 39 = 78 g / mol

O : 1 x 16 = 16 g / mol

`````````````````````````` Mm = 94 g / mol - Na2O

Na : 2 x 23 = 46 g / mol

O : 1 x 16 = 16 g / mol

```````````````````````````````` Mm = 62 g / mol - CaSO4

Ca : 1 x 40 = 40 g / mol

S : 1 x 32 = 32 g / mol

O : 4 x 16 = 64 g / mol

`````````````````````````````` Mm = 136 g / mol - PbCl2

Pb : 1 x 207 = 207 g / mol

Cl : 2 x 35.

45 = 70.

9 g / mol

```````````````````````````````````` Mm = 277.

9 g / mol - Li2O

Li : 2 x 7 = 14 g / mol

O : 1 x 16 = 16 g / mol

```````````````````````````` Mm = 30 g / mol - NaOH

Na : 1 x 23 = 23 g / mol

O : 1 x 16 = 16 g / mol

H : 1 x 1 = 1 g / mol

```````````````````````````````` Mm = 40 g / mol - FeO

Fe : 1 x 56 = 56 g / mol

O : 1 x 16 = 16 g / mol

```````````````````````````` Mm = 72 g / mol - Fe2O3

Fe : 2 x 56 = 112 g / mol

O.

3 x 16 = 48 g / mol

`````````````````````````````````` Mm = 160 g / mol - Mn2O7

Mn : 2 x 55 = 110 g / mol O : 7 x 16 = 112 g / mol

`````````````````````````````````` Mm = 222 g / mol - Hg2O

Hg = 2 x 200.

6 = 401.

2 g / mol O = 1 x 16 = 16 g / mol

`````````````````````````````````````` Mm = 417.

2 - Al2O3

Al : 2 X 27 = 54 g / mol O : 3 x 16 = 48 g / mol

`````````````````````````````` Mm = 102 g / mol - V2O5

V : 2 x 51 = 102 g / mol

O : 5 x 16 = 80 g / mol

`````````````````````````````` Mm = 182 g / mol - MgO

Mg : 1 x 24 = 24 g / mol O : 1 X 16 = 16 g / mol

`````````````````````````````` Mm = 40 g / mol - CuO

Cu : 1 x 63.

5 = 63.

5 g / mol O : 1 x 16 = 16 g / mol

`````````````````````````````````` Mm = 49.

5 g / mol - PtO2

Pt : 1 x 195 = 195 g / mol O : 2 x 16 = 32 g / mol

`````````````````````````````` Mm = 227 g / mol - CdO

Cd = 1 x 112.

4 = 112.

4 g / mol O = 1 x 16 = 16 g / mol

```````````````````````````````````````` Mm = 128.

4 g / mol.