Averigua la masa de sulfuro de estaño (ii) que se obtendra al añadir un exceso de sulfuro de sodio a una disolucion que contiene 20 g de cloruro de estaño (ii). En la reaccion tambien se produce cloruro de sodio.
En resumen
Na2S + SnCl2 → SnCl + 2 NaCl Mm SnCl2 = 189. 61 g / mol SnS = 150. 77 g / mol calcular gramos de SnS g SnS = 20 g SnCl2 x 1 mol SnCl2 x 1 mol SnS x 150. 77 g SnS `````````````````` ```````````````` ````````````````````` 189. 61 g SnCl2 1 mol SnCl2 1 mol SnS g SnS = 15. 90.
Na2S + SnCl2 → SnCl + 2 NaCl
Mm SnCl2 = 189.
61 g / mol SnS = 150.
77 g / mol
calcular gramos de SnS
g SnS = 20 g SnCl2 x 1 mol SnCl2 x 1 mol SnS x 150.
77 g SnS `````````````````` ```````````````` ````````````````````` 189.
61 g SnCl2 1 mol SnCl2 1 mol SnS
g SnS = 15.
90.