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2. Calcule la formula molecular o verdadera de a partir de las siguientes formulas empíricas y pesos moleculares A?

2. Calcule la formula molecular o verdadera de a partir de las siguientes formulas empíricas y pesos moleculares A. C2H5 y 58, 1g a. C6H15 b. C2H5 c. C4H10 d. C H B. CH2O y 60, 0 g a. CHO b. C3H2O4 c. C2H4O2 d. CH2O C. KClO3 y 122, 5 g a. KClO3 b. K2Cl2O6 c. K3Cl3O9 d. K4Cl4O12.

En resumen

A. C2H5 y 58, 1 g Mm FE C : 2 x 12 = 24 g / mol H : 5 x 1 = 5 g / mol ```````````````````````````` Mm = 29 g / mol n = Mm FM ```````````` Mm FE n = 58.

Mejor respuesta

Soofiiaaor
2

A. C2H5 y 58, 1 g

Mm FE

C : 2 x 12 = 24 g / mol

H : 5 x 1 = 5 g / mol

```````````````````````````` Mm = 29 g / mol

n = Mm FM ```````````` Mm FE

n = 58.

1 g / mol / 29 g / mol = 2

n = 2

FM : (C2H5)n = (C2H5)₂ = C₄H₁₀ RESPUESTA : C

B : CH2O y 60 g

Mm FE

C : 1 x 12 = 12 g / mol

H : 2 x 1 = 2 g / mol

O : 1 x 16 = 16 g / mol

```````````````````````````` Mm = 30 g / mol

n = Mm FM ```````````` Mm FE

n = 60 g / mol / 30 g / mol = 2

n = 2

FM : (CH₂O)n = (CH2O)₂ = C₂H₄O₂ RESPUESTA : C

C.

KClO3 y 122.

5 g

Mm FE

K : 1 x 39 = 39 g / mol

Cl : 1 x 35.

5 = 35.

5 g / mol

O : 3 x 16 = 48 g / mol

```````````````````````````` Mm = 122.

5 g / mol

n = Mm FM ```````````` Mm FE

n = 122.

5 g / mol / 122.

5 g / mol = 1

n = 1

FM : (KClO3)n = (KClO3)₁ = KClO3 RESPUESTA : A.