(x + 4)al cuadrado = 2x(5x - 1) - 7(x - 2)?
(x + 4)al cuadrado = 2x(5x - 1) - 7(x - 2).
(x + 4)al cuadrado = 2x(5x - 1) - 7(x - 2).
Pregunta de Matemáticas · 1 respuesta · 8 votos · mejor respuesta de Keythia
En resumen
<img src="https://tex.z-dn.net/?f=%28x%2B4%29%5E%7B2%7D%20%3D%202x%285x-1%29%20-%207%28x-2%29" /><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B8x%20%2B16%20%3D%2010x%5E%7B2%7D%20-%202x%20-7x%20%2B%2014" /><img src="https://tex.z-dn.net/?
<img src="https://tex.z-dn.net/?f=%28x%2B4%29%5E%7B2%7D%20%3D%202x%285x-1%29%20-%207%28x-2%29" /><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B8x%20%2B16%20%3D%2010x%5E%7B2%7D%20-%202x%20-7x%20%2B%2014" /><img src="https://tex.z-dn.net/?f=0%20%3D%2010x%5E%7B2%7D%20-%20%20x%5E%7B2%7D%20-2x%20-7x%20-8x%20%2B%2014-16" /><img src="https://tex.z-dn.net/?f=0%20%3D%209x%5E%7B2%7D%20-17x%20-2" />9x 1x - 2 - 18x + x = - 17x(9x + 1)(x - 2) = 09x + 1 = 0 y x - 2 = 09x = - 1 y x = 2x = - 1 / 9CS = { ( - 1 / 9 ; 2) } Eternamente.
Axllxa.
<img src="https://tex.z-dn.net/?f=%28x%2B4%29%5E%7B2%7D%20%3D%202x%285x-1%29%20-%207%28x-2%29" /><img src="https://tex.z-dn.net/?