(x + 1)(6x - 2) = (2x + 4)(3x + 2)?
(x + 1)(6x - 2) = (2x + 4)(3x + 2).
(x + 1)(6x - 2) = (2x + 4)(3x + 2).
Pregunta de Matemáticas · 1 respuesta · 4 votos · mejor respuesta de Mdr99
En resumen
(6x ^ 2 - 2x + 6x - 2) = (6x ^ 2 + 4x + 12x + 8) 6x ^ 2 + 4x - 2 = 6x ^ 2 + 16x + 8 6x ^ 2 - 6x ^ 2 + 4x - 16x = 8 + 2 - 12x = 10 x = 10 / - 12 x = - 5 / 6.
(6x ^ 2 - 2x + 6x - 2) = (6x ^ 2 + 4x + 12x + 8)
6x ^ 2 + 4x - 2 = 6x ^ 2 + 16x + 8
6x ^ 2 - 6x ^ 2 + 4x - 16x = 8 + 2 - 12x = 10
x = 10 / - 12
x = - 5 / 6.
(6x ^ 2 - 2x + 6x - 2) = (6x ^ 2 + 4x + 12x + 8) 6x ^ 2 + 4x - 2 = 6x ^ 2 + 16x + 8 6x ^ 2 - 6x ^ 2 + 4x - 16x = 8 + 2 - 12x = 10 x = 10 / - 12 x = - 5 / 6.