[tex]6 \ times x + 3x - 7 = 16[ / tex][tex]6 \ times \ : x + 8 - x = 58[ / tex][tex]5 \ times x + 15 = 4x + 16[ / tex][tex]5 \ times x + 3 - 4 = 2 \ times x + 14[ / tex][tex]3 \ times x + 12 = 5 \ tim?

Question

[tex]6 \ times x + 3x - 7 = 16[ / tex] [tex]6 \ times \ : x + 8 - x = 58[ / tex] [tex]5 \ times x + 15 = 4x + 16[ / tex] [tex]5 \ times x + 3 - 4 = 2 \ times x + 14[ / tex] [tex]3 \ times x + 12 = 5 \ times x + 20 + 1 - 3 \ times x[ / tex] AYUDAAA URGENTE​.

Genesnarayzorrrr · Accepted Answer

Respuesta : Explicación paso a paso : 6 * x + 3x - 7 = 16

6x + 3x = 16 + 79x = 23x = 23 / 96 * x + 8 - x = 58

6x - x = 58 - 85x = 50x = 50 / 5x = 105 * x + 15 = 4x + 16

5x - 4x = 15 - 15x = 15 * x + 3 - 4 = 2 * x + 145x + 3 - 4 = 2x + 145x - 2x = 14 - 3 + 43x = 15x = 15 / 3x = 5

3 * x + 12 = 5 * x + 20 + 1 - 3 * x

3x + 12 = 5x + 21 - 3x3x + 12 = 2x + 213x - 2x = 21 - 12x = 9.

[tex]6 \ times x + 3x - 7 = 16[ / tex][tex]6 \ times \ : x + 8 - x = 58[ / tex][tex]5 \ times x + 15 = 4x + 16[ / tex][tex]5 \ times x + 3 - 4 = 2 \ times x + 14[ / tex][tex]3 \ times x + 12 = 5 \ tim?

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Escribe como única potencia aplicando las propiedades de las potencias :[tex] 25 \ times 5 {} ^ {4} [ / tex][tex]3 \ times 9 \ times {3} ^ {0} \ times 27[ / tex][tex] {5} ^ {6} \ div ( {3} ^ {2} \ tim?

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[tex]2 \ times ^ {2} + 2 \ times [ / tex]?

[tex]6 \ times x + 3x - 7 = 16[ / tex][tex]6 \ times \ : x + 8 - x = 58[ / tex][tex]5 \ times x + 15 = 4x + 16[ / tex][tex]5 \ times x + 3 - 4 = 2 \ times x + 14[ / tex][tex]3 \ times x + 12 = 5 \ tim?

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Escribe como única potencia aplicando las propiedades de las potencias :[tex] 25 \ times 5 {} ^ {4} [ / tex][tex]3 \ times 9 \ times {3} ^ {0} \ times 27[ / tex][tex] {5} ^ {6} \ div ( {3} ^ {2} \ tim?

[tex]50 \ times 51[ / tex]​?

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[tex]3 \ times < 20 + \ times [ / tex]?

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