Tengo que resolverestas ecuaciones de numeros complejos : a)x ^ 2 - 9 = 0 b)5x ^ 2 - 15 = 0 c)x ^ 2 - 3x - 4 = 0 d)2x ^ 2 - 5x + 1 = 0 e)7x ^ 2 - 7x = 0 f)2x ^ 2 + 3x = 0.
ax² + bx + c = 0
A)x ^ 2 - 9 = 0 x ^ 2 = 9 x1 = 3 x2 = - 3 S = { - 3, 3}
b)5x ^ 2 - 15 = 0 5x ^ 2 = 15 x ^ 2 = 3 x1 = raiz de 3 x2 = - raiz de 3 S = {( - raiz de 3), (raiz de 3)}
c)x ^ 2 - 3x - 4 = 0 Factirizando (x - 4)(x + 1) = 0 x - 4 = 0 x1 = 4 x + 1 = 0 x2 = - 1 S = { - 1 , 4}
d)2x ^ 2 - 5x + 1 = 0 Fórmula general x = [ - b + / - (raiz delta)] / 2a delta = b2 - 4.
A. c = 25 - 4(2)(1) = 17 x = [5 + / - (raiz de17)] / 4 x1 = [5 - (raiz de 17)] / 4 x2 = [5 + (raiz de 17)] / 4 S = {[5 - (raiz de 17] / 4], [5 + (razi de 17)] / 4]}
e)7x ^ 2 - 7x = 0 Factorizando 7x(x - 1) = 0 7x = 0 x1 = 0 x - 1 = 0 x2 = 1 S = {0, 1}
f)2x ^ 2 + 3x = 0 x(2x + 3) = 0 x1 = 0 2x + 3 = 0 x2 = - 3 / 2 S = { - 3 / 2, 0}.
Resolver : (ax + bx + cx) / x = Sacamos factor comun x [x(a + b + b)] / x = Simplificamos la x a + b + c Respuesta. (ax + bx + cx) / x = a + b + c.
Calcular. (ax + bx + cx) / x Factorizas sacas factor comun x x(a + b + c) / x Simplificas x (a + b + c) Respuesta. A + b + c.
X. (a + b + c) esa es la respuesta.