Si el numeral ?
Si el numeral . Hallar a mas b [tex](3a)(2a)[ \ frac{a}{2}] (a - 3)[ \ frac{b}{3}] [ / tex].
6Suuckit4me
En resumen
(3a)(2b)[a / 2](a - 3)[b / 3] = 0 (6a²b / 2)(ab - 3b / 3) = 0 6a³b² - 18a²b² / 6 = 0 6a²b²(a - 3) / 6 = 0 a²b²(a - 3) = 0 a³b² - 3a²b² = 0 a³b² = 3a²b² a³b² / a²b² = 3 a = 3 (3a)(2b)[a / 2](a - 3)[b / 3] a(3 + 1 / 2)b(2 + 1 / 3)(a - 3) (21 / 2)(7b / 2)(a - 3) 0 b = 0 a + b = 3.
Mejor respuesta
Zarytha
(3a)(2b)[a / 2](a - 3)[b / 3] = 0
(6a²b / 2)(ab - 3b / 3) = 0
6a³b² - 18a²b² / 6 = 0
6a²b²(a - 3) / 6 = 0
a²b²(a - 3) = 0
a³b² - 3a²b² = 0
a³b² = 3a²b²
a³b² / a²b² = 3
a = 3
(3a)(2b)[a / 2](a - 3)[b / 3]
a(3 + 1 / 2)b(2 + 1 / 3)(a - 3)
(21 / 2)(7b / 2)(a - 3)
0
b = 0
a + b = 3.