Si : a / 3 = b / 7 = c / 9 = d / 5 = 9 / 2hallar : ( a + b + c + d) tema razones y proporciones aritmetica urgente?
Si : a / 3 = b / 7 = c / 9 = d / 5 = 9 / 2 hallar : ( a + b + c + d) tema razones y proporciones aritmetica urgente.
2CarliiRom
Si : a / 3 = b / 7 = c / 9 = d / 5 = 9 / 2 hallar : ( a + b + c + d) tema razones y proporciones aritmetica urgente.
En resumen
A / 3 = 9 / 2 a = 27 / 2 b / 7 = 9 / 2 b = 63 / 2 c / 9 = 9 / 2 c = 81 / 2 d / 5 = 9 / 2 d = 45 / 2 a + b + c + d = 27 / 2 + 63 / 2 + 81 / 2 + 45 / 2 = 216 / 2 = 108.
Ana2099
A / 3 = 9 / 2 a = 27 / 2
b / 7 = 9 / 2 b = 63 / 2
c / 9 = 9 / 2 c = 81 / 2
d / 5 = 9 / 2 d = 45 / 2
a + b + c + d = 27 / 2 + 63 / 2 + 81 / 2 + 45 / 2 = 216 / 2 = 108.