MatemáticasBásico1 respuestas

(Sen(30)÷Cos(45)) + (Sec(45)÷Tang(45))?

(Sen(30)÷Cos(45)) + (Sec(45)÷Tang(45)).

6Natyrm1998

En resumen

Sen 30 = 0. 5 cos 45 = 0. 7071 sen 30 / cos 45 = 0. 5 / 0. 7071 = 0. 7071 sec 45 = 1 / cos 45 = 1. 4142 tan 45 = 1 sec 45 / tan 45 = 1. 4142 / 1 = 1. 4142 sumamos 0. 7071 + 1. 4142 = 2. 121 Buen día!

Mejor respuesta

Migahi16

10

Sen 30 = 0.

5

cos 45 = 0.

7071

sen 30 / cos 45 = 0.

5 / 0.

7071 = 0.

7071

sec 45 = 1 / cos 45 = 1.

4142

tan 45 = 1

sec 45 / tan 45 = 1.

4142 / 1 = 1.

4142

sumamos 0.

7071 + 1.

4142 = 2.

121

Buen día!