Sea el polinomio :P(x) = (ax + b)(x + 2) - 3(x ^ 2 - c)Si : P(x) = 0 ?
Sea el polinomio : P(x) = (ax + b)(x + 2) - 3(x ^ 2 - c) Si : P(x) = 0 . Hallar "a + b + c". (álgebra ) ayudenme es para hoy .
Sea el polinomio : P(x) = (ax + b)(x + 2) - 3(x ^ 2 - c) Si : P(x) = 0 . Hallar "a + b + c". (álgebra ) ayudenme es para hoy .
Pregunta de Matemáticas · 1 respuesta · 8 votos · mejor respuesta de Cakethecat01
En resumen
<img src="https://tex.z-dn.net/?f=P%28x%29%3D%28ax%2Bb%29%28x%2B2%29-3%28x%5E2-c%29" /> <img src="https://tex.z-dn.net/?f=P%28x%29%3Dax%5E2%2B2ax%2Bbx%2B2b-3x%5E2%2B3c" /> <img src="https://tex.z-dn.net/?
<img src="https://tex.z-dn.net/?f=P%28x%29%3D%28ax%2Bb%29%28x%2B2%29-3%28x%5E2-c%29" />
<img src="https://tex.z-dn.net/?f=P%28x%29%3Dax%5E2%2B2ax%2Bbx%2B2b-3x%5E2%2B3c" />
<img src="https://tex.z-dn.net/?f=P%28x%29%3D%28a-3%29x%5E2%2B%282a%2Bb%29x%2B%282b%2B3c%29" />
Como P(x) = 0
entonces
<img src="https://tex.z-dn.net/?f=a-3%3D0" />entonces <img src="https://tex.z-dn.net/?f=a%3D3" />
<img src="https://tex.z-dn.net/?f=2a%2Bb%3D0" /> entonces <img src="https://tex.z-dn.net/?f=b%3D-2a%3D-2%283%29%3D-6" />
<img src="https://tex.z-dn.net/?f=2b%2B3c%3D0" />entonces <img src="https://tex.z-dn.net/?f=3c%3D-2b%3D-2%28-6%29%3D12%20" />entonces <img src="https://tex.z-dn.net/?f=c%3D4" />
luego [img = 10].
<img src="https://tex.z-dn.net/?f=P%28x%29%3D%28ax%2Bb%29%28x%2B2%29-3%28x%5E2-c%29" /> <img src="https://tex.z-dn.net/?f=P%28x%29%3Dax%5E2%2B2ax%2Bbx%2B2b-3x%5E2%2B3c" /> <img src="https://tex.z-dn.