MatemáticasBásico1 respuestas

Resolver los siguientes sistemas?

Resolver los siguientes sistemas. (metodos de igualacion y sust) A. 2 . (x - 3) - 3 = (y + 3) : 2 (x - 4) : 2 - (2y - 1) : 4 = - (1 / 2) elevado al - 2 B. - 3 / 2 . (x - 4y) = - 4 (6y + 5x) : 10 - 1 / 3 = - 2 / 5y.

10Amanuelasmlg

En resumen

EJERCICIO 01 2. (x - 3) - 3 = (y + 3) : 2 <img src="https://tex.z-dn.net/?f=%202%20%28x-3%29%20-%203%20%3D%20%5Cfrac%7B%28y%2B3%29%7D%7B2%7D%20" /> <img src="https://tex.z-dn.net/?f=2x%20-%206%20-%203%3D%20%5Cfrac%7B%28y%2B3%29%7D%7B2%7D%20" /> <img src="https://tex.z-dn.net/?

Mejor respuesta

Yele004

6

EJERCICIO 01

2.

(x - 3) - 3 = (y + 3) : 2

<img src="https://tex.z-dn.net/?f=%202%20%28x-3%29%20-%203%20%3D%20%5Cfrac%7B%28y%2B3%29%7D%7B2%7D%20" />

<img src="https://tex.z-dn.net/?f=2x%20-%206%20-%203%3D%20%5Cfrac%7B%28y%2B3%29%7D%7B2%7D%20" />

<img src="https://tex.z-dn.net/?f=2%20%282x%20-%209%29%3D%20y%2B3" />

<img src="https://tex.z-dn.net/?f=4x%20-%2018%20%3D%20y%2B3" />

<img src="https://tex.z-dn.net/?f=4x%20-%2021%20%3D%20y" /> .

ECUACIÓN I

(x - 4) : 2 - (2y - 1) : 4 = - (1 / 2) elevado al - 2

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x-4%29%7D%7B2%7D%20-%20%20%5Cfrac%7B%282y-1%29%7D%7B4%7D%20%3D%20-%20%28%5Cfrac%7B-1%7D%7B2%7D%20%29%20%5E%7B-2%7D%20%20%20" />

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%282x-8%29%20-%20%282y-1%29%7D%7B4%7D%20%3D%20-%20%28%5Cfrac%7B2%7D%7B1%7D%20%29%20%5E%7B2%7D%20" />

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x%20-%202y%20-%207%7D%7B4%7D%20%3D%20-%204" />

<img src="https://tex.z-dn.net/?f=2x%20-%202y%20-%207%20%3D%20-%2016" />

<img src="https://tex.z-dn.net/?f=2x%20-%202y%20%3D%20-%209" /> .

ECUACIÓN II

Reemplazando la ECUACIÓN I en la ECUACIÓN II

[img = 10]

[img = 11]

[img = 12]

[img = 13]

[img = 14]

Hallamos el valor de "y"

[img = 15]

[img = 16]

[img = 17]

EJERCICIO 02 - 3 / 2 .

(x - 4y) = - 4

[img = 18]

[img = 19]

[img = 20]

[img = 21]

[img = 22] .

ECUACIÓN I

(6y + 5x) : 10 - 1 / 3 = - 2 / 5y

[img = 23]

[img = 24]

[img = 25]

[img = 26] .

ECUACIÓN II

Reemplazando la ECUACIÓN I en la ECUACIÓN II

[img = 27]

[img = 28]

[img = 29]

[img = 30]

[img = 31]

[img = 32]

Hallamos el valor de "x"

[img = 33]

[img = 34]

[img = 35]

[img = 36]

[img = 37].