Resolver las siguientes ecuaciones1) x ^ 2 - x + 52 = 02)x ^ 2 - 12x - 120 = 03)x ^ 2 + 4x = 0?
Resolver las siguientes ecuaciones 1) x ^ 2 - x + 52 = 0 2)x ^ 2 - 12x - 120 = 0 3)x ^ 2 + 4x = 0.
Resolver las siguientes ecuaciones 1) x ^ 2 - x + 52 = 0 2)x ^ 2 - 12x - 120 = 0 3)x ^ 2 + 4x = 0.
ax² + bx + c = 0
En resumen
1) x² - x + 52 = 0 x = [ - b±√(b² - 4ac)] / (2a) x = [ - ( - 1)±√(( - 1)² - 4 * 1 * 52)] / (2 * 1) x = [1±√(1 - 208)] / 2 x = [1±√( - 207)] / 2 x = [1±14. 388 i] / 2 x1 = [1 + 14. 388 i] / 2 x2 = [1 - 14. 388 i] / 2 x1 = 0. 5 + 7. 194 i x2 = 0. 5 - 7.
1) x² - x + 52 = 0 x = [ - b±√(b² - 4ac)] / (2a) x = [ - ( - 1)±√(( - 1)² - 4 * 1 * 52)] / (2 * 1) x = [1±√(1 - 208)] / 2 x = [1±√( - 207)] / 2 x = [1±14.
388 i] / 2 x1 = [1 + 14.
388 i] / 2 x2 = [1 - 14.
388 i] / 2 x1 = 0.
5 + 7.
194 i x2 = 0.
5 - 7.
194 i
2)x² - 12x - 120 = 0 x = [ - b±√(b² - 4ac)] / (2a) x = [ - ( - 12)±√(( - 12)² - 4 * 1 * ( - 120))] / (2 * 1) x = [12±√(144 + 480)] / 2 x = [12±√(624)] / 2 x = [12±24.
98] / 2 x1 = [12 + 24.
98] / 2 x2 = [12 - 24.
98] / 2 x1 = [36.
98] / 2 x2 = - 12.
98 / 2 x1 = 18.
49 x2 = - 6.
49
3)x² + 4x = 0 x(x + 4)
x = 0 x + 4 = 0
x1 = 0 x2 = - 4.
. Espero que te sirva, salu2!
7x / 10 = 28 7x = 280 x = 40 (16x + 40 - 120) / 8 = x + 2 16x - 80 = 8x + 16 8x = 96 x = 12 (2x + 2 + 14x) / 14 = x - 2 2x + 2 + 14x = 14x - 2 2x + 2 = - 2 2x = - 4 x = - 2 (16x + 24 - 25x + 10) / 40 = (31x + 27) / 6…