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Resolver las siguientes ecuaciones1) x ^ 2 - x + 52 = 02)x ^ 2 - 12x - 120 = 03)x ^ 2 + 4x = 0?

Resolver las siguientes ecuaciones 1) x ^ 2 - x + 52 = 0 2)x ^ 2 - 12x - 120 = 0 3)x ^ 2 + 4x = 0.

Calculadora interactiva

ax² + bx + c = 0

En resumen

1) x² - x + 52 = 0 x = [ - b±√(b² - 4ac)] / (2a) x = [ - ( - 1)±√(( - 1)² - 4 * 1 * 52)] / (2 * 1) x = [1±√(1 - 208)] / 2 x = [1±√( - 207)] / 2 x = [1±14. 388 i] / 2 x1 = [1 + 14. 388 i] / 2 x2 = [1 - 14. 388 i] / 2 x1 = 0. 5 + 7. 194 i x2 = 0. 5 - 7.

Mejor respuesta

Martin8az
1

1) x² - x + 52 = 0 x = [ - b±√(b² - 4ac)] / (2a) x = [ - ( - 1)±√(( - 1)² - 4 * 1 * 52)] / (2 * 1) x = [1±√(1 - 208)] / 2 x = [1±√( - 207)] / 2 x = [1±14.

388 i] / 2 x1 = [1 + 14.

388 i] / 2 x2 = [1 - 14.

388 i] / 2 x1 = 0.

5 + 7.

194 i x2 = 0.

5 - 7.

194 i

2)x² - 12x - 120 = 0 x = [ - b±√(b² - 4ac)] / (2a) x = [ - ( - 12)±√(( - 12)² - 4 * 1 * ( - 120))] / (2 * 1) x = [12±√(144 + 480)] / 2 x = [12±√(624)] / 2 x = [12±24.

98] / 2 x1 = [12 + 24.

98] / 2 x2 = [12 - 24.

98] / 2 x1 = [36.

98] / 2 x2 = - 12.

98 / 2 x1 = 18.

49 x2 = - 6.

49

3)x² + 4x = 0 x(x + 4)

x = 0 x + 4 = 0

x1 = 0 x2 = - 4.