Resolver :(3x + 2) – ( - x – 1) = (2x + 4) + (x + 3)4x + 9 = 2x – 3 + x3( x + 2) – 5 ( 4 – 7x) = 8?
Resolver : (3x + 2) – ( - x – 1) = (2x + 4) + (x + 3) 4x + 9 = 2x – 3 + x 3( x + 2) – 5 ( 4 – 7x) = 8.
Resolver : (3x + 2) – ( - x – 1) = (2x + 4) + (x + 3) 4x + 9 = 2x – 3 + x 3( x + 2) – 5 ( 4 – 7x) = 8.
En resumen
(3x + 2) – ( - x – 1) = (2x + 4) + (x + 3) 3x + 2 + x + 1 = 2x + 4 + x + 3 3x + x - 2x - x = 4 + 3 - 2 - 1 x = 4 4x + 9 = 2x – 3 + x 4x - 2x - x = - 3 - 9 x = - 12 3( x + 2) – 5 ( 4 – 7x) = 8 3 x + 6 - 20 + 35x = 8 3x + 35x = 8 - 6 + 20 38x = 22 x = 22 / 38 x = 11 / 19.
(3x + 2) – ( - x – 1) = (2x + 4) + (x + 3)
3x + 2 + x + 1 = 2x + 4 + x + 3
3x + x - 2x - x = 4 + 3 - 2 - 1 x = 4
4x + 9 = 2x – 3 + x
4x - 2x - x = - 3 - 9 x = - 12
3( x + 2) – 5 ( 4 – 7x) = 8
3 x + 6 - 20 + 35x = 8
3x + 35x = 8 - 6 + 20 38x = 22 x = 22 / 38 x = 11 / 19.
X² + x - 2 = 0 ⇒ (x + 2) (x - 1) = 0 x 2 x - 1 x + 2 = 0 ∨ x - 1 = 0 x = - 2 ∨ x = 1 cs = { - 2, 1}.
Ahi te va la solucion.
X ^ x ^ x = 3 entonces x ^ x ^ x + x ^ x es 3 + 3 = 6 porque dondex ^ x tenia que descomponer habiendo x ^ x ^ x.