Porfas ayúdenme ni tengo quien me ayude las 6?
Porfas ayúdenme ni tengo quien me ayude las 6.
Porfas ayúdenme ni tengo quien me ayude las 6.
Pregunta de Matemáticas · 1 respuesta · 4 votos · mejor respuesta de KatGarcia
En resumen
<img src="https://tex.z-dn.net/?f=%204x%5E%7B2%7D%20%3D%201" /> 4x ^ {2} - 1 = 0 (2x + 1)(2x - 1) = 0 2x + 1 = 0 2x - 1 = 0 2x = - 1 2x = 1 <img src="https://tex.z-dn.net/?f=x%20%3D%20-%20%5Cfrac%7B1%7D%7B2%7D%20" /> <img src="https://tex.z-dn.net/?
<img src="https://tex.z-dn.net/?f=%204x%5E%7B2%7D%20%3D%201" />
4x ^ {2} - 1 = 0
(2x + 1)(2x - 1) = 0
2x + 1 = 0 2x - 1 = 0
2x = - 1 2x = 1
<img src="https://tex.z-dn.net/?f=x%20%3D%20-%20%5Cfrac%7B1%7D%7B2%7D%20" /> <img src="https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20" />
<img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-x%20-56%20%3D%200%0A" />
x - 8x + 7 - 8x + 7x = - x
(x - 8)(x + 7) = 0
x - 8 = 0 x + 7 = 0x = 8 x = - 7
CS = ( - 7 ; 8)
<img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B%209x%20%3D%200%20" />
x(x + 9) = 0
x = 0 x + 9 = 0 x = - 9
CS = ( - 9 ; 0).
<img src="https://tex.z-dn.net/?f=%204x%5E%7B2%7D%20%3D%201" /> 4x ^ {2} - 1 = 0 (2x + 1)(2x - 1) = 0 2x + 1 = 0 2x - 1 = 0 2x = - 1 2x = 1 <img src="https://tex.z-dn.net/?