MatemáticasBásico1 respuestas

POR FAVOR AYÚDENME CON ESTOS EJERCICIOS GRACIAS•6 – (3 – 10) + (4 – 8 + 2) – (7 + 5 – 1) =•3 – (5 – 6 + 2) + (4 – 3 + 1) =•(5 – 6 ) + (4 – 1) – (3 – 4 ) + (4) =•(1) x (2) / (2 + 5 + 2) =•(2) x (5) + (?

POR FAVOR AYÚDENME CON ESTOS EJERCICIOS GRACIAS • 6 – (3 – 10) + (4 – 8 + 2) – (7 + 5 – 1) = • 3 – (5 – 6 + 2) + (4 – 3 + 1) = • (5 – 6 ) + (4 – 1) – (3 – 4 ) + (4) = • (1) x (2) / (2 + 5 + 2) = • (2) x (5) + (5 – 3) / (2) =.

En resumen

· 6 - (3 - 10) + (4 - 8 + 2) - (7 + 5 - 1) = 6 - ( - 7) + ( - 2) - 11 = 0· 3 - (5 - 6 + 2) + (4 - 3 + 1) = 3 - 1 + 2 = 4· (5 - 6) + (4 - 1) - (3 - 4) + 4 = - 1 + 3 - 1 + 4 = 5· 1 x 2 / (2 + 5 + 2) = 2 / 9· 2 x 5 + (5 - 3) / 2 = 6.

Mejor respuesta

Patiolv
3

· 6 - (3 - 10) + (4 - 8 + 2) - (7 + 5 - 1) = 6 - ( - 7) + ( - 2) - 11 = 0· 3 - (5 - 6 + 2) + (4 - 3 + 1) = 3 - 1 + 2 = 4· (5 - 6) + (4 - 1) - (3 - 4) + 4 = - 1 + 3 - 1 + 4 = 5· 1 x 2 / (2 + 5 + 2) = 2 / 9· 2 x 5 + (5 - 3) / 2 = 6.