Me podrías ayudar con este sistema de ecuación : (se puede resolver por el método que quieras) x + 1 y - 1 - - - - - - + - - - - - - = 0 3 2 x + 2y x + y + 2 - - - - - - - - - - - - - - - - - - - - = 0 3 4.
ax² + bx + c = 0
Respuesta :
(x + 1) / 3 + (y - 1) / 2 = 0
(x + 2y) / 3 - (x + y + 2) / 4 = 0
(x + 1) / 3 + (y - 1) / 2 = 0
(2(x + 1) + 3(y - 1)) / 6 = 0
2(x + 1) + 3(y - 1) = 0
2x + 2 + 3y - 3 = 0
2x + 3y - 1 = 0
2x + 3y = 1
(x + 2y) / 3 - (x + y + 2) / 4 = 0
(4(x + 2y) - 3(x + y + 2)) / 12 = 0
4(x + 2y) - 3(x + y + 2) = 0
4x + 8y - 3x - 3y - 6 = 0
x + 5y - 6 = 0
x + 5y = 6
2x + 3y = 1
x + 5y = 6
2x + 3y = 1
2(x) + 2(5y) = 2(6)
2x + 3y = 1
2x + 10y = 12
2x + 10y = 12 - 2x - 3y = - 1 - - - - - - - - - - - - - - - - - - - - 7y = 11
7y = 11
y = 11 / 7
x + 5y = 6
x + 5(11 / 7) = 6
x + 55 / 7 = 6
x = 6 - 55 / 7
x = (42 - 55) / 7
x = - 13 / 7
x = - 13 / 7
y = 11 / 7.
Veamos :
(x + 1) / 3 + ( y - 1) / 2 = 0
(x + 1) / 3 = - ( y - 1) / 2
2(x + 1) = 3 ( - y + 1)
2x + 2 = - 3y + 3
2x = - 3y + 1
x = ( - 3y + 1 ) / 2
Hallamos la otra "x" :
(x + 2y) / 3 - (x + y + 2) / 4 = 0
(x + 2y) / 3 = (x + y + 2) / 4
4(x + 2y) = 3(x + y + 2)
4x + 8y = 3x + 3y + 6
4x - 3x = 3y - 8y + 6
x = - 5y + 6 = > Igualamos las "x" :
( - 3y + 1) / 2 = - 5y + 6 - 3y + 1 = 2( - 5y + 6) - 3y + 1 = - 10y + 12 - 3y + 10y = 12 - 1
7y = 11
y = 11 / 7 = > Hallamos "x" :
x = - 5y + 6
x = - 5(11 / 7) + 6
x = - 55 / 7 + 6
x = - 13 / 7
Espero te sirva !
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