Me ayufan por favorrre?

1) 9x ^ 2 - 25 = 0

9x ^ 2 = 25

x ^ 2 = 25 / 9

x = raiz de 25 / 9

x = 5 / 3

2) x ^ 2 + 2 = 6

x ^ 2 = 6 - 2

x ^ 2 = 4

x = raiz de 4

x = 2

3) 3x ^ 2 + 17x + 18 = - 2

3x ^ 2 + 17x + 20 = 0

aplicar bhaskara

4) 23x ^ 2 = 2(200 - x ^ 2)

23x ^ 2 = 400 - 2x ^ 2

23x ^ 2 - 2x ^ 2 = 400

21x ^ 2 = 400

x ^ 2 = 400 / 21

x ^ 2 = 400 / 21

5) x ^ 2 = 2x - 1

x ^ 2 - 2x + 1 = 0

es un binomio cuadrado

(x - 1) ^ 2

x = 1

6) 2x - 4 = x ^ 2 - 2x - x ^ 2 + 2x + 2 x - 4 = 0 - x ^ 2 + 4x - 4 = 0 - 1(x ^ 2 - 4x + 4 ) = 0

es un binomio cuadrado - 1 * (x - 2) ^ 2 = 0

x = 2

7) x ^ 2 + (7 - x) ^ 2 = 25

x ^ 2 + 49 - 14 x + x ^ 2 - 25 = 0

2x ^ 2 - 14 x + 24 = 0

resolver por bhaskara

8) x ^ 2 + (x + 2) ^ 2 = 580

x ^ 2 + x ^ 2 + 4x + 4 - 580 = 0

2x ^ 2 + 4x - 576 = 0

resuelvo por bhaskara

9)

x - 2 / (x + 1) = 5 / (x + 1) - 7

(x * (x + 1) - 2) / (x + 1) = 5 - (7(x + 1)) / (x + 1)

x ^ 2 + x - 2 = 5 - (7x + 7)

x ^ 2 + x - 2 + 7x + 7 = 5

x ^ 2 + 8 + 5 = 5

x ^ 2 + 8 + 5 - 5 = 0

x ^ 2 + 8 = 0

x = - + (raiz de 8 ) * i

10) 16x - 8 = - 1 / x

x * (16x - 8) = - 1

16 x ^ 2 - 8x + 1 = 0

resolver por bhaskara.