Me ayudan a resolver estaecuación - 2(m + 3) = 5 ?
Me ayudan a resolver esta ecuación - 2(m + 3) = 5 . (2m + 1) + m.
Me ayudan a resolver esta ecuación - 2(m + 3) = 5 . (2m + 1) + m.
ax² + bx + c = 0
En resumen
- 2(m + 3) = 5 . (2m + 1) + m - 2m - 6 = 10m + 5 + m - 6 - 5 = 10m + m + 2m - 11 = 13m - 11 / 13 = m.
- 2(m + 3) = 5 .
(2m + 1) + m - 2m - 6 = 10m + 5 + m - 6 - 5 = 10m + m + 2m - 11 = 13m - 11 / 13 = m.
M2 + 7 = 88 m2 = 88 - 7 m2 = 81 m2 = m = 40. 5.
14x - 2 = 0 14x = 2 x = 2 / 14 → 1 / 7 El valor de x = 1 / 7(fracción simplificada).
((4R - 2) / 5) = 1 - 2R y (( 2 - T) / 2) = - ((T - 10) / 6) 4R - 2 = 5(1 - 2R) 6(2 - T) = 2( - T + 10) 4R - 2 = 5 - 10R 12 - 6T = - 2T + 20 4R + 10R = 5 + 2 12 - 20 = - 2T + 6T 14R = 7 - 8 = 4T R = 7 / 14 T = - 8 / 4 R…