K = (sen30?
K = (sen30. Cos60 + tg60. Cos30) \ (sen37 + tg37).
En resumen
K = [sen(30)cos(60) + tg(60)cos(30)] / [sen(37) + tg(37)] k = [0, 25 + 1, 5] / [0, 6 + 0, 75] k = 1, 75 / 1, 35 k = . 1, 3.
Mejor respuesta
K = [sen(30)cos(60) + tg(60)cos(30)] / [sen(37) + tg(37)]
k = [0, 25 + 1, 5] / [0, 6 + 0, 75]
k = 1, 75 / 1, 35
k = .
1, 3.