John needed to hang a picture he bought?
John needed to hang a picture he bought. He drilled a hole ⅜ inch in diameter. The nail he intended to use was 0. 5 inch in diameter. Was the hole too small or too large? By how much.
5Carol16ben
En resumen
The hole was too small by 1 / 8 or 0. 125 inEl agujero era demasiado pequeño por 1 / 8 o 0. 125 pulgStep by step explanation : If we express the nail value in fractions of inches, this is equal to : 0.
Mejor respuesta
Yona15
The hole was too small by 1 / 8 or 0.
125 inEl agujero era demasiado pequeño por 1 / 8 o 0.
125 pulgStep by step explanation : If we express the nail value in fractions of inches, this is equal to :
0.
5 in = 1 / 2 "
Now if the hole that was made with the drill has a diameter of 3 / 8 ", in linear value it is
3 / 8 " = 0.
375 in
We compare both values Nail Hole 0.
5 in > 0.
375 in
The hole is very small, we calculate the difference :
0.
5 in 0.
375 in
0.
125 in ⇒ 1 / 8 "Explicación paso a paso : Si expresamos el valor del clavo en fracciones de pulgadas, este es igual a : 0.
5 pulg = 1 / 2"Ahora si el agujero que se realizo con el taladro tiene un diámetro de 3 / 8", en valor lineal es 3 / 8" = 0.
375 pulgComparamos ambos valores Clavo Agujero 0.
5 pulg > 0.
375 pulgEl agujero es muy pequeño, calculamos la diferencia : 0.
5 pulg 0.
375 pulg 0.
125 pulg ⇒ 1 / 8".
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