Hallar "x"en 8 ^ x + 2 = 16 ^ x - 5?

<img src="https://tex.z-dn.net/?f=8%5E%7Bx%2B2%7D%20%3D%2016%5E%7Bx-5%7D" /> (Aplicando logaritmo base 2 tenemos)

<img src="https://tex.z-dn.net/?f=Log%E2%82%82%208%5E%7Bx%2B2%7D%20%3D%20Log%E2%82%82%2016%5E%7Bx-5%7D" />(Descomponiendo el 8 y el 16 en base2)

<img src="https://tex.z-dn.net/?f=Log%E2%82%82%202%5E%7B3%28x%2B2%29%7D%20%3D%20Log%E2%82%82%202%5E%7B4%28x-5%29%7D" /> (Aplicando propiedad Log x² = 2Logx)

<img src="https://tex.z-dn.net/?f=3%28x%2B2%29Log%E2%82%82%282%29%3D4%28x-5%29Log%E2%82%82%282%29%20" /> (Sabiendo que Log₂(2) = 1)

[text] 3x + 6 = 4x - 20 [ / tex]

[text] x = 26 [ / tex].