Hallar "x" en :(4 ^ (x + 1)) (8 ^ (x - 1)) = 16 ^ (x + 3)?
Hallar "x" en : (4 ^ (x + 1)) (8 ^ (x - 1)) = 16 ^ (x + 3).
Hallar "x" en : (4 ^ (x + 1)) (8 ^ (x - 1)) = 16 ^ (x + 3).
Pregunta de Matemáticas · 1 respuesta · 10 votos · mejor respuesta de Bloodofnick
En resumen
<img src="https://tex.z-dn.net/?f=Hola%21%21%20" /> <img src="https://tex.z-dn.net/?f=4%5E%7Bx%2B1%7D%20%2A8%5E%7Bx-1%7D%20%3D16%5E%7Bx%2B3%7D%20" /> <img src="https://tex.z-dn.net/?
<img src="https://tex.z-dn.net/?f=Hola%21%21%20" />
<img src="https://tex.z-dn.net/?f=4%5E%7Bx%2B1%7D%20%2A8%5E%7Bx-1%7D%20%3D16%5E%7Bx%2B3%7D%20" />
<img src="https://tex.z-dn.net/?f=2%5E%7B2%28x%2B1%29%7D%20%2A2%5E%7B3%28x-1%29%7D%20%3D2%5E%7B4%28x%2B3%29%7D%20" />
<img src="https://tex.z-dn.net/?f=2%5E%7B2x%2B2%2B3x-3%7D%20%3D2%5E%7B4x%2B12%7D%20" />
Se eliminan las bases de ambos miembros :
<img src="https://tex.z-dn.net/?f=2x%2B2%2B3x-3%3D4x%2B12" />
<img src="https://tex.z-dn.net/?f=5x-1%3D4x%2B12" />
<img src="https://tex.z-dn.net/?f=5x-4x%3D12%2B1" />
<img src="https://tex.z-dn.net/?f=x%3D13" />
Respuesta : El valor de la incógnita (x) es 13
Suerte y saludos !
<img src="https://tex.z-dn.net/?f=Hola%21%21%20" /> <img src="https://tex.z-dn.net/?f=4%5E%7Bx%2B1%7D%20%2A8%5E%7Bx-1%7D%20%3D16%5E%7Bx%2B3%7D%20" /> <img src="https://tex.z-dn.net/?