Hallar la suma de los radicales. 1. 3√2 + 4√2 + 5√2 = 12√2 2. 3√7 + 8√7 + 4√7 = 15√7 3. [tex] \ frac{1}2 \ sqrt{2} + 3 \ sqrt{2} + \ sqrt{2}[ / tex] 4. √5 + 2√5 + 3√5 = 6√5 5. 2√2 + [tex] \ frac{1}4 \ sqrt{2} + \ frac{3}4 \ sqrt{2} = 3 \ sqrt{2}[ / tex] 6. 4√2 + 2√2 + [tex] \ frac{1}2 \ sqrt{2} = \ frac{13}2 \ sqrt{2}[ / tex].
3√2 + 4√2 + 5√2 =
(3 + 4 + 5)√2 =
12√2 - - - > respuesta
3√7 + 8√7 + 4√7 =
(3 + 8 + 4)√7 =
15√7 - - - - > respuesta
1 / 2√2 + 3√2 + √2 =
(1 / 2 + 3 + 1)√2 =
(1 / 2 + 2 * 3 / 2 + 1 * 2)√2 / 2
(1 / 2 + 6 / 2 + 2)√2 / 2 =
(1 + 6 + 2)√2 / 2
(9 / 2)√2 - - - >Respuesta9 / 2)
√5 + 2√5 + 3√5 =
(1 + 2 + 3)√5 =
6√5 - - - > respuesta
2√2 + 1 / 4√2 + 3 / 4√2 =
(2 + 1 / 4 + 3 / 4)√2 =
(2 * 4 + 1 + 3)√2 / 4 =
(8 + 1 + 3)√2 / 4 =
12√2 / 4 = 3√2 - - >respuesta
4√2 + 2√2 + 1 / 2√2 =
(4 + 2 + 1 / 2)√2 =
(4 * 2 + 2 * 2 + 1)√2 / 2
(8 + 4 + 1)√2 / 2 =
(13 / 2)√2 - - - > respuesta.
√4 = 2 o - 2 √8 = √4 * 2 = 2√2 irracional √18 = √9 * 2 = 3 * √2 irracional √10 = √10 * 10 = √10² = 10² / ² = 10 o - 10.
D.
La respuesta es 2 : ).