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Hallar el conjunto solucion de cada ecuacion[tex] \ frac{1}{5} (6x + 1) = 1[ / tex]5 - [tex] \ frac{1}{4} x[ / tex] = 10 - (x - 1)[tex] \ frac{15 - x}{x} = \ frac{1}{2} [ / tex][tex] \ frac{1x}{2} - \?

Hallar el conjunto solucion de cada ecuacion [tex] \ frac{1}{5} (6x + 1) = 1[ / tex] 5 - [tex] \ frac{1}{4} x[ / tex] = 10 - (x - 1) [tex] \ frac{15 - x}{x} = \ frac{1}{2} [ / tex] [tex] \ frac{1x}{2} - \ frac{2}{3} = \ frac{1}{4} x - 1[ / tex].

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ax² + bx + c = 0

En resumen

6x + 1 = 5 21 / 4x = 10 - x + 1 2(15 - x) = x 6x = 5 - 1 24x + 4x = 44 30 - x = x 6x = 4 28x = 44 30 = 2x x = 4 / 6 = 2 / 3 x = 22 / 14 = 11 / 7 15 = x 2(3x - 4) = 3(x - 4) 6x - 8 = 3x - 12 6x - 3x = - 12 + 8 3x = - 4 x = - 4 / 3.

Mejor respuesta

Kattiacp

5

6x + 1 = 5 21 / 4x = 10 - x + 1 2(15 - x) = x

6x = 5 - 1 24x + 4x = 44 30 - x = x

6x = 4 28x = 44 30 = 2x

x = 4 / 6 = 2 / 3 x = 22 / 14 = 11 / 7 15 = x

2(3x - 4) = 3(x - 4)

6x - 8 = 3x - 12

6x - 3x = - 12 + 8 3x = - 4 x = - 4 / 3.