Halla la solucion en cada caso b)1 / 5x - 7 = - 3 / 2x - 8 c)x - 5 / x + 6 = 4 / 3 d)6 / 5 = x - 7 / 2(x + 1)?
Halla la solucion en cada caso b)1 / 5x - 7 = - 3 / 2x - 8 c)x - 5 / x + 6 = 4 / 3 d)6 / 5 = x - 7 / 2(x + 1).
Halla la solucion en cada caso b)1 / 5x - 7 = - 3 / 2x - 8 c)x - 5 / x + 6 = 4 / 3 d)6 / 5 = x - 7 / 2(x + 1).
En resumen
1 / 5x - 7 = - 3 / 2x - 8 2x - 8 = - 3(5x - 7) 2x - 8 = - 15x + 21 17x = 29 x = 29 / 17 x - 5 / x + 6 = 4 / 3 3(x - 5) = 4(x + 6) 3x - 15 = 4x + 24 x = - 39 6 / 5 = x - 7 / 2(x + 1) 12(x + 1) = 5(x - 7) 12x + 12 = 5x - 35 7x = - 47 x = - 47 / 7.
1 / 5x - 7 = - 3 / 2x - 8
2x - 8 = - 3(5x - 7)
2x - 8 = - 15x + 21
17x = 29
x = 29 / 17
x - 5 / x + 6 = 4 / 3
3(x - 5) = 4(x + 6)
3x - 15 = 4x + 24
x = - 39
6 / 5 = x - 7 / 2(x + 1)
12(x + 1) = 5(x - 7)
12x + 12 = 5x - 35
7x = - 47
x = - 47 / 7.
(−12) • x = −48 −12x = −48 x = −48 / −12 x = 4.
Respuesta : : vExplicación paso a paso :
Respuesta : es mas pomes el signo ( + ).