Find the perimeter of the quadrilateral if x = 2?
Find the perimeter of the quadrilateral if x = 2.
Find the perimeter of the quadrilateral if x = 2.
4x² + 8 x
[ 4 (2)² + 8 (2) ] [4 (4) + 16] (16 + 16) (32) [ ( 3 x² - 5 x + 20 ) ]
[ ( 3 (2)² - 5 (2) + 20 ) ] [ 3 ( 4) - 10 + 20 ] ( 12 - 10 + 20 ) (2 + 22) ( 22)
[ ( 7 x + 30 ) ]
[ ( 7 (2) + 30 ) ] (14 + 30 ) (44)
Perímetro es la suma de los lados, y ya tenemos los lados :
32 + 22 + 44 + 31 54 + 75 129.
Ok, let´s see the answer the sides are : 4x 5x + 3 7x - 1 we have the perimeter, then : 4x + 5x + 3 + 7x - 1 = 130 16x = 130 - 2 16x = 128 x = 128 / 16 x = 8 cm also : 1° lado = 4 * 8 = 32cm 2° lado = 5 * 8 + 3 = 43 3°…
Of what thing.
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90 + 8x - 1 + 4x + 7 = 18012x + 6 = 9012x = 84x = 7So : 1. 8x - 1 = 56 - 1 = 55°2. 4x + 7 = 28 + 5 = 35°.