Find the coordinates of the vertices of a Triangle whose sides have midpoints at (2, 1) ( - 1, 3)and ( - 2, 5)?
Find the coordinates of the vertices of a Triangle whose sides have midpoints at (2, 1) ( - 1, 3)and ( - 2, 5) .
Find the coordinates of the vertices of a Triangle whose sides have midpoints at (2, 1) ( - 1, 3)and ( - 2, 5) .
Respuesta : Envío archivo pdfExplicación paso a paso :
Hi! The distance around a triangle, better noun as de "perimeter of a triangle" is the total distance around the outside, which can be found by adding together the length of each side. Perimeter (P) = Length A + Length…
Ok, let´s see the answer the sides are : 4x 5x + 3 7x - 1 we have the perimeter, then : 4x + 5x + 3 + 7x - 1 = 130 16x = 130 - 2 16x = 128 x = 128 / 16 x = 8 cm also : 1° lado = 4 * 8 = 32cm 2° lado = 5 * 8 + 3 = 43 3°…
The formula is A = B + b / 2.
90 + 8x - 1 + 4x + 7 = 18012x + 6 = 9012x = 84x = 7So : 1. 8x - 1 = 56 - 1 = 55°2. 4x + 7 = 28 + 5 = 35°.
Respuesta : The condition is that angle is in betwen the two sides1. - First using cosines law , we'll find the third side2. - Usin the Area Heron's formula we'll find the areaExplicación paso a paso : 1. - If you know…