F(3x - 1) = 2x + 3 / p(x) = 4x - 1 / hallar = P[F(2)]?
F(3x - 1) = 2x + 3 / p(x) = 4x - 1 / hallar = P[F(2)].
F(3x - 1) = 2x + 3 / p(x) = 4x - 1 / hallar = P[F(2)].
En resumen
F(3x - 1) - - > f(2) - - > 3x - 1 = 2 - - > 3x = 3 - - > x = 1 f(2) = 2(1) + 3 f(2) = 5 P(f(2)) = 4(5) - 1 P(f(2)) = 20 - 1 P(f(2)) = 19.
F(3x - 1) - - > f(2) - - > 3x - 1 = 2 - - > 3x = 3 - - > x = 1
f(2) = 2(1) + 3
f(2) = 5
P(f(2)) = 4(5) - 1
P(f(2)) = 20 - 1
P(f(2)) = 19.