Encontrar terminosAn = 5 + (n - 1)4 : a1, a5, a10?
Encontrar terminos An = 5 + (n - 1)4 : a1, a5, a10.
Encontrar terminos An = 5 + (n - 1)4 : a1, a5, a10.
Pregunta de Matemáticas · 1 respuesta · mejor respuesta de Feryangie
En resumen
A(n) = 5 + (n - 1)⁴ A(1) = 5 + (1 - 1)⁴ = 5 + 0 = 5 → A(1) = 5 A(5) = 5 + (5 - 1)⁴ = 5 + 256 = 261 → A(5) = 261 A(10) = 5 + (10 - 1)⁴ = 5 + 6561 = 6566 → A(10) = 6566.
A(n) = 5 + (n - 1)⁴
A(1) = 5 + (1 - 1)⁴ = 5 + 0 = 5 → A(1) = 5
A(5) = 5 + (5 - 1)⁴ = 5 + 256 = 261 → A(5) = 261
A(10) = 5 + (10 - 1)⁴ = 5 + 6561 = 6566 → A(10) = 6566.
A(n) = 5 + (n - 1)⁴ A(1) = 5 + (1 - 1)⁴ = 5 + 0 = 5 → A(1) = 5 A(5) = 5 + (5 - 1)⁴ = 5 + 256 = 261 → A(5) = 261 A(10) = 5 + (10 - 1)⁴ = 5 + 6561 = 6566 → A(10) = 6566.