Ecuación doble incógnitaa)5x - 2y = - 12b)x + 3y = 1?
Ecuación doble incógnita a)5x - 2y = - 12 b)x + 3y = 1.
Ecuación doble incógnita a)5x - 2y = - 12 b)x + 3y = 1.
ax² + bx + c = 0
En resumen
A) Simplifying 5x + - 2y = 12 Solving 5x + - 2y = 12 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '2y' to each side of the equation.
A) Simplifying
5x + - 2y = 12
Solving
5x + - 2y = 12
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '2y' to each side of the equation.
5x + - 2y + 2y = 12 + 2y
Combine like terms : - 2y + 2y = 0
5x + 0 = 12 + 2y
5x = 12 + 2y
Divide each side by '5'.
X = 2.
4 + 0.
4y
Simplifying
x = 2.
4 + 0.
4y
B)Simplifyingx + 3y = 1
Solving
x + 3y = 1
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add ' - 3y' to each side of the equation.
X + 3y + - 3y = 1 + - 3y
Combine like terms : 3y + - 3y = 0
x + 0 = 1 + - 3y
x = 1 + - 3y
Simplifying
x = 1 + - 3y.
Resolver : (ax + bx + cx) / x = Sacamos factor comun x [x(a + b + b)] / x = Simplificamos la x a + b + c Respuesta. (ax + bx + cx) / x = a + b + c.
Por favor despeja I y listo. No me alcanzó el espacio.
Primero, pasamos los términos que tienen "x" al primer miembro y los que no tienen "x" al segundo miembro, quedaría así : ax - bx < 2a ^ 2 - 3ab + b ^ 2 Factorizamos en ambos miembros x(a - b) < (2a - b) (a - b)…