Determinar el valor de x en las ecuaciones4x = 2x - 128x - 24 = 5x7xmas12 = 4x - 17?
Determinar el valor de x en las ecuaciones 4x = 2x - 12 8x - 24 = 5x 7xmas12 = 4x - 17.
Determinar el valor de x en las ecuaciones 4x = 2x - 12 8x - 24 = 5x 7xmas12 = 4x - 17.
ax² + bx + c = 0
En resumen
4x = 2x - 12 4x - 2x = - 12 2x = 12 x = 12 / 2 = 6 8x - 24 = 5x 8x - 5x = 24 3x = 24 x = 24 / 3 = 8 7x + 12 = 4x - 17 7x - 4x + 12 = - 17 3x = - 12 - 17 3x = - 29 x = - 29 / 3.
4x = 2x - 12
4x - 2x = - 12
2x = 12
x = 12 / 2 = 6
8x - 24 = 5x
8x - 5x = 24
3x = 24
x = 24 / 3 = 8
7x + 12 = 4x - 17
7x - 4x + 12 = - 17
3x = - 12 - 17
3x = - 29
x = - 29 / 3.
Resolver.
4x = 2x - 12
4x - 2x = - 12
2x = - 12
x = - 12 / 2
x = - 6
8x - 24 = 5x
8x - 5x = 24
x = 24
x = 24 / 3
x = 8
7x + 12 = 4x - 17
7x - 4x = - 17 - 12
3x = - 29
x = - 29 / 3.
Ya alo tengo xd pues seria de dos maneras la primera x(x + 5) = 24 x = 3 y sino xal cuadrado + 5x - 24 = 0 x. 8 x. - 3 x - 3 = O x = 3 y listo.
X = b - apor lo tanto a es positivo.