Let's take functionsfffandgggfor example : f(x) = \ dfrac{x + 1}{3}f(x) = 3x + 1f, left parenthesis, x, right parenthesis, equals, start fraction, x, plus, 1, divided by, 3, end fractionandg(x) = 3x - 1g(x) = 3x−1g, left parenthesis, x, right parenthesis, equals, 3, x, minus, 1.
Notice howf(5) = 2f(5) = 2f, left parenthesis, 5, right parenthesis, equals, 2andg(2) = 5g(2) = 5g, left parenthesis, 2, right parenthesis, equals, 5.
[Please show me the calculations]f(5)f, left parenthesis, 5, right parenthesis55ff \ begin{aligned}f(x)& = \ dfrac{x + 1}{3} \ \ \ \ f( \ blueD{5})& = \ dfrac{ \ blueD5 + 1}{3} \ \ \ \ & = \ goldD2 \ end{aligned}g(2)g, left parenthesis, 2, right parenthesis22gg \ begin{aligned}g(x)& = 3x - 1 \ \ \ \ g( \ goldD{2})& = 3( \ goldD2) - 1 \ \ \ \ & = \ blueD5 \ end{aligned} \ blueD{5}5ff \ goldD{2}2gg \ blueD{5}5.