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Danika concludes that the following functions are inverses of each other because f(g(x)) = x?

Danika concludes that the following functions are inverses of each other because f(g(x)) = x. Do you agree with Danika? Explain your reasoning. F(x) = |x| g(x) = –x.

7Estercarcamo19

Mejor respuesta

Marinafernandez

7

Let's take functionsfffandgggfor example : f(x) = \ dfrac{x + 1}{3}f(x) = ​3​​x + 1​​f, left parenthesis, x, right parenthesis, equals, start fraction, x, plus, 1, divided by, 3, end fractionandg(x) = 3x - 1g(x) = 3x−1g, left parenthesis, x, right parenthesis, equals, 3, x, minus, 1.

Notice howf(5) = 2f(5) = 2f, left parenthesis, 5, right parenthesis, equals, 2andg(2) = 5g(2) = 5g, left parenthesis, 2, right parenthesis, equals, 5.

[Please show me the calculations]f(5)f, left parenthesis, 5, right parenthesis55ff \ begin{aligned}f(x)& = \ dfrac{x + 1}{3} \ \ \ \ f( \ blueD{5})& = \ dfrac{ \ blueD5 + 1}{3} \ \ \ \ & = \ goldD2 \ end{aligned}g(2)g, left parenthesis, 2, right parenthesis22gg \ begin{aligned}g(x)& = 3x - 1 \ \ \ \ g( \ goldD{2})& = 3( \ goldD2) - 1 \ \ \ \ & = \ blueD5 \ end{aligned} \ blueD{5}5ff \ goldD{2}2gg \ blueD{5}5.