Solucionando el planteamiento tenemos : 1.
Probabilidad de que 9 o más utilicen Twitter : 0, 0001.
2. Probabilidad de que máximo dos usen esa red : 0, 7306.
◘Desarrollo : Aplicamos el criterio estadístico de Distribución Poisson, por medio de la siguiente fórmula : X≈Poiss (λ = x)<img src="https://tex.z-dn.net/?f=P%28X%3Dx%29%3D%5Cfrac%7Be%5E%7B-%5Clambda%7D%2A%5Clambda%5E%7Bx%7D%7D%7Bx%21%7D" />1.
Probabilidad de que 9 o más utilicen Twitter : X≈Poiss (λ = 30 * 0, 06 = 1, 8)<img src="https://tex.z-dn.net/?f=P%28X%5Cgeq9%29%3D1-%20P%28x%3C9%29" /><img src="https://tex.z-dn.net/?f=P%28X%3C9%29%3DP%28X%3D0%29%2BP%28X%3D1%29%2BP%28X%3D2%29%2BP%28X%3D3%29%2BP%28X%3D4%29%2BP%28X%3D5%29%2BP%28X%3D6%29%2BP%28X%3D7%29%2BP%28X%3D8%29%2BP%28X%3D9%29" /><img src="https://tex.z-dn.net/?f=P%28X%3D0%29%3D%5Cfrac%7Be%5E%7B-1%2C8%7D%2A1%2C8%5E%7B0%7D%7D%7B0%21%7D" /><img src="https://tex.z-dn.net/?f=P%28X%3D0%29%3D0%2C1653" /><img src="https://tex.z-dn.net/?f=P%28X%3D1%29%3D%5Cfrac%7Be%5E%7B-1%2C8%7D%2A1%2C8%5E%7B1%7D%7D%7B1%21%7D" /><img src="https://tex.z-dn.net/?f=P%28X%3D1%29%3D0%2C2975" /><img src="https://tex.z-dn.net/?f=P%28X%3D2%29%3D%5Cfrac%7Be%5E%7B-1%2C8%7D%2A1%2C8%5E%7B2%7D%7D%7B2%21%7D" /><img src="https://tex.z-dn.net/?f=P%28X%3D2%29%3D0%2C2678" /><img src="https://tex.z-dn.net/?f=P%28X%3D3%29%3D%5Cfrac%7Be%5E%7B-1%2C8%7D%2A1%2C8%5E%7B3%7D%7D%7B3%21%7D" />[img = 10][img = 11][img = 12][img = 13][img = 14][img = 15][img = 16][img = 17][img = 18][img = 19][img = 20][img = 21][img = 22][img = 23][img = 24][img = 25][img = 26][img = 27]2.
Probabilidad de que máximo dos usen esa red : [img = 28][img = 29][img = 30].