Ayuda log 8 512Log 5 512?
Ayuda log 8 512 Log 5 512.
Ayuda log 8 512 Log 5 512.
En resumen
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Lued812
<img src="https://tex.z-dn.net/?f=%5Clog%20_8%5Cleft%28512%5Cright%29" />
<img src="https://tex.z-dn.net/?f=%5Cmathrm%7BReescribir%5C%3A%7D512%5Cmathrm%7B%5C%3Autilizando%5C%3Apotencias%3A%7D%5Cquad%20512%3D8%5E3" />
<img src="https://tex.z-dn.net/?f=%3D%5Clog%20_8%5Cleft%288%5E3%5Cright%29" />
<img src="https://tex.z-dn.net/?f=%5Cmathrm%7BAplicar%5C%3Alas%5C%3Apropiedades%5C%3Ade%5C%3Alos%5C%3Alogaritmos%7D%3A%5Cquad%20%5Clog%20_a%5Cleft%28x%5Eb%5Cright%29%3Db%5Ccdot%20%5Clog%20_a%5Cleft%28x%5Cright%29" />
<img src="https://tex.z-dn.net/?f=%3D3%5Clog%20_8%5Cleft%288%5Cright%29" />
<img src="https://tex.z-dn.net/?f=%5Cmathrm%7BAplicar%5C%3Alas%5C%3Apropiedades%5C%3Ade%5C%3Alos%5C%3Alogaritmos%7D%3A%5Cquad%20%5Clog%20_a%5Cleft%28a%5Cright%29%3D1" /><img src="https://tex.z-dn.net/?f=%5Clog%20_8%5Cleft%288%5Cright%29%3D1" /> = 3(1) = 3
<img src="https://tex.z-dn.net/?f=%5Clog%20_5%5Cleft%28512%5Cright%29" />
<img src="https://tex.z-dn.net/?f=%5Cmathrm%7BReescribir%5C%3A%7D512%5Cmathrm%7B%5C%3Autilizando%5C%3Apotencias%3A%7D%5Cquad%20512%3D2%5E9" />
<img src="https://tex.z-dn.net/?f=%3D%5Clog%20_5%5Cleft%282%5E9%5Cright%29" />
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[img = 12].
Vicky2612
Fácil lo que debes hacer es :
Convertir a forma exponencial :
8 ^ x = 512 = 8 ^ 3
x = 3
El logaritmo de 512 ala base 8 = 3.
Como todo está en base 10 entonces : Log 1000 = log10 ^ 3 = 3 log 0. 001 = log 1 / 1000 = log 1000 ^ - 1 = - 1log1000 = - 1log10 ^ 3 = - 1(3) = - 3 log 1 / 1000 = log 1000 ^ - 1 = - 1log1000 = - 1log10 ^ 3 = - 1(3) = -…
Por propiedad de logaritmos, seria : Log(3 - x) + Log(3 + x) = Log(3 - x)(3 + x) = Log(9 - x²).
Aplicando propiedades operacionales de otencis 36 = 2 ^ 2x3 ^ 2 log36 = x = log(2 ^ 2x3 ^ 2) = log2 ^ 2 + log3 ^ 2 = 2log2 + 2log3 = 2(m) + 2(n)x = 2(m + n) respuesta.
La respuesta es la a.