A)[tex] {3} ^ {3} - 2 \ times \ sqrt{64} + {7} ^ {0} = [ / tex]?
A) [tex] {3} ^ {3} - 2 \ times \ sqrt{64} + {7} ^ {0} = [ / tex] .
A) [tex] {3} ^ {3} - 2 \ times \ sqrt{64} + {7} ^ {0} = [ / tex] .
En resumen
Respuesta : <img src="https://tex.z-dn.net/?f=3%5E%7B3%7D" /> - 2x<img src="https://tex.z-dn.net/?f=%5Csqrt%7B64%7D" /> + <img src="https://tex.z-dn.net/?
Respuesta : <img src="https://tex.z-dn.net/?f=3%5E%7B3%7D" /> - 2x<img src="https://tex.z-dn.net/?f=%5Csqrt%7B64%7D" /> + <img src="https://tex.z-dn.net/?f=7%5E%7B0%7D" />21 - 2x8 + 7 = elevado al cero no existe, la raiz de 64 es 8, 3 al cuadrado es 3x3x3 = 2121 - 2x8 + 719x8 + 7 = 27 - 2 = 2519x15 = 8 + 7 = 15285 = 19x15285 = 285.