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Aplicar las propiedades y luego resolver?

Aplicar las propiedades y luego resolver. A)[tex] ( - 4) ^ {5} . ( - 4) ^ {6} : ( - 4) ^ {8} = [ / tex] B)[tex] (( - 5) ^ {6} . ( - 5)) ^ {2} : ( - 5) ^ {11} = [ / tex] C)[tex](( - 3) ^ {9} . ( - 2) ^ {8} ) : (( - 3) ^ {7} . ( - 2) ^ {5} ) = [ / tex].

En resumen

A) ( - 4)⁵ . ( - 4)⁶ : ( - 4)⁸ = ( - 4)⁵⁺⁶ : ( - 4)⁸ = ( - 4)¹¹ : ( - 4)⁸ = ( - 4)¹¹ . ( - 4)⁻⁸ = ( - 4)¹¹⁻⁸ = ( - 4)³ B) (( - 5)⁶ . ( - 5) )² : ( - 5)¹¹ = (( - 5)⁶⁺¹)² : ( - 5)¹¹ = (( - 5)⁷)² : ( - 5)¹¹ = ( - 5)¹⁴ : ( - 5)¹¹ = ( - 5) ¹⁴⁻¹¹ = ( - 5) ³ C) (( - 3)⁹ .

Mejor respuesta

Jonathancruz17
5

A)

( - 4)⁵ .

( - 4)⁶ : ( - 4)⁸ = ( - 4)⁵⁺⁶ : ( - 4)⁸ = ( - 4)¹¹ : ( - 4)⁸ = ( - 4)¹¹ .

( - 4)⁻⁸ = ( - 4)¹¹⁻⁸ = ( - 4)³

B)

(( - 5)⁶ .

( - 5) )² : ( - 5)¹¹ = (( - 5)⁶⁺¹)² : ( - 5)¹¹ = (( - 5)⁷)² : ( - 5)¹¹ = ( - 5)¹⁴ : ( - 5)¹¹ = ( - 5) ¹⁴⁻¹¹ = ( - 5) ³

C)

(( - 3)⁹ .

( - 2)⁸) : (( - 3)⁷).

( - 2)⁵) = (( - 3)⁹.

( - 3)⁻⁷ .

( - 2)⁸ .

( - 2)⁻⁵) = (( - 3)⁹⁻⁷ .

( - 2)⁸⁻⁵) =

(( - 3)².

( - 2)³).

Otras 1 respuestas

Respuesta 2

Yadira8tatiana
3

A)

( - 4)⁵ .

( - 4)⁶ : ( - 4)⁸ = ( - 4)⁵⁺⁶ : ( - 4)⁸ = ( - 4)¹¹ : ( - 4)⁸ = ( - 4)¹¹ .

( - 4)⁻⁸ = ( - 4)¹¹⁻⁸ = ( - 4)³

B)

(( - 5)⁶ .

( - 5) )² : ( - 5)¹¹ = (( - 5)⁶⁺¹)² : ( - 5)¹¹ = (( - 5)⁷)² : ( - 5)¹¹ = ( - 5)¹⁴ : ( - 5)¹¹ = ( - 5) ¹⁴⁻¹¹ = ( - 5) ³

C)

(( - 3)⁹ .

( - 2)⁸) : (( - 3)⁷).

( - 2)⁵) = (( - 3)⁹.

( - 3)⁻⁷ .

( - 2)⁸ .

( - 2)⁻⁵) = (( - 3)⁹⁻⁷ .

( - 2)⁸⁻⁵) =

(( - 3)².

( - 2)³).