A - b = 3, hallar 2a5b(base 8) - b3a(base8)?

A - b = 3, hallar 2a5b(base 8) - b3a(base8) Hola!

Los números están en base 8, entonces primero vamos a pasarlos a base decimal : <img src="https://tex.z-dn.net/?f=%202a5b_%28_8_%29%20%3D%202.8%5E3%20%2B%20a.8%5E2%2B5.8%5E1%2Bb.8%5E0%5C%5C%5C%5C%202a5b_%28_8_%29%20%3D%202.512%20%2B%20a.64%2B5.8%2Bb.1%5C%5C%5C%5C%20%5Cboxed%7B2a5b_%28_8_%29%20%3D%201024%20%2B%2064a%2B40%2Bb%7D%5C%5C%5C%5C%20%5C%5C%20b3a_%28_8_%29%3D%20b.8%5E2%2B3.8%5E1%2Ba.8%5E0%20%5C%5C%20%5C%5C%20b3a_%28_8_%29%3D%20b.64%2B3.8%2Ba.1%20%5C%5C%20%5C%5C%20%5Cboxed%7B%20b3a_%28_8_%29%3D%2064b%2B24%2Ba%20%7D" /> Ahora reemplazamos el valor de a y calculamos, CUIDADO con los signos <img src="https://tex.z-dn.net/?f=%20a-b%3D3%5Cqquad%5Cto%5Cqquad%20a%3D%203%20%2B%20b%2C%20entonces%5C%5C%5C%5C%20%20%202a5b_%28_8_%29%20-%20b3a_%28_8_%29%20%3D%201024%20%2B%2064a%2B40%2Bb%20-%20%2864b%2B24%2Ba%20%29%20%5C%5C%5C%5C%20%20%202a5b_%28_8_%29%20-%20b3a_%28_8_%29%20%3D%201064%20%2B%2064a%2Bb%20-%2064b-24-a%5C%5C%5C%5C%20Reemplazamos%20%5C%20el%20%5C%20valor%5C%20de%20%5C%20a%20%5C%5C%5C%5C%20%20%202a5b_%28_8_%29%20-%20b3a_%28_8_%29%20%3D%201064%20%2B%2064%283%2Bb%29%2B40%2Bb%20-%2064b-24-%283%2Bb%29%5C%5C%5C%5C%20%20%20%20%202a5b_%28_8_%29%20-%20b3a_%28_8_%29%20%3D%201064%20%2B%20192%20%2B%2064b%2B40%2Bb%20-%2064b-24-3-b%5C%5C%5C%5C%20%20%20%202a5b_%28_8_%29%20-%20b3a_%28_8_%29%20%3D%201064%20%2B%20192%20%2B40-24-3%5Cqquad%20se%5C%20cancelan%20%5C%20%22b%22%20%5C%5C%5C%5C%20%20%20%202a5b_%28_8_%29%20-%20b3a_%28_8_%29%20%3D%201269%20" />

Respuesta <img src="https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7B2a5b_%28_8_%29%20-%20b3a_%28_8_%29%20%3D%201269%7D%7D%20%20%20%20" />

Espero que te sirva, salu2!