(a - b - 1) ^ 2 como se resuelve?
(a - b - 1) ^ 2 como se resuelve?
(a - b - 1) ^ 2 como se resuelve?
En resumen
Resolución : <img src="https://tex.z-dn.net/?f=%20%28a-b-1%29%5E%7B2%7D%3D%28a-b-1%29%28a-b-1%29%3Da%5E%7B2%7D-ab-a-ab%2Bb%5E%7B2%7D%2Bb-a%2Bb%2B2%3D%5C%5Ca%5E%7B2%7D%2Bb%5E%7B2%7D-2ab-2a%2B2d%2B2b%5C%5CFactor..comun%3A%5C%5Ca%5E%7B2%7D%2Bb%5E%7B2%7D%2B2%281%2Bb-a-ab%29%20" />.
Resolución : <img src="https://tex.z-dn.net/?f=%20%28a-b-1%29%5E%7B2%7D%3D%28a-b-1%29%28a-b-1%29%3Da%5E%7B2%7D-ab-a-ab%2Bb%5E%7B2%7D%2Bb-a%2Bb%2B2%3D%5C%5Ca%5E%7B2%7D%2Bb%5E%7B2%7D-2ab-2a%2B2d%2B2b%5C%5CFactor..comun%3A%5C%5Ca%5E%7B2%7D%2Bb%5E%7B2%7D%2B2%281%2Bb-a-ab%29%20" />.
Con una simplificación de exponentes.
C = 5 c2 : c al cuadrado y asi b = 4 = >c2 = a2 + b2 25 = a2 + 16 a = 3 a = 3 b = 4 c = 5 sen = co / h cos = ca / h ca = cateto adyacente tag = co / ca co = cateto opuesto ctg = ca / co h = hipotenusa sec = h / ca Cosec…