MatemáticasBásico1 respuestas

6(3X - 4) + 2[3(4X - 2) + 6 - 2(3X - 4) + X – 3X] = 25X + 20?

6(3X - 4) + 2[3(4X - 2) + 6 - 2(3X - 4) + X – 3X] = 25X + 20.

En resumen

6(3x - 4) + 2[3(4x - 2) + 6 - 2(3x - 4) + x – 3x] = 25x + 2018x−24 + 2[3(4x−2) + 6−2(3x−4) + x−3] = 25x + 2018x−24 + [−6 + 6−6x + 8 + x−3x] = 25x + 2018x−24 + 2(6x−6 + 6 + 8 + x−3x) = 25x + 2018x−24 + (8x + 16) = 25x + 2026x−8 = 25x + 20x−8 = 20x = 20 + 8x = 28.

Mejor respuesta

ArichixD
1

6(3x - 4) + 2[3(4x - 2) + 6 - 2(3x - 4) + x – 3x] = 25x + 2018x−24 + 2[3(4x−2) + 6−2(3x−4) + x−3] = 25x + 2018x−24 + [−6 + 6−6x + 8 + x−3x] = 25x + 2018x−24 + 2(6x−6 + 6 + 8 + x−3x) = 25x + 2018x−24 + (8x + 16) = 25x + 2026x−8 = 25x + 20x−8 = 20x = 20 + 8x = 28.