- 3x - [ - 6x - (3 - x)] = 9 + (x - 1) paso a paso?
- 3x - [ - 6x - (3 - x)] = 9 + (x - 1) paso a paso.
En resumen
- 3x - ( - 6x - (3 - x)) = 9 + (x - 1) - 3x - ( - 6x - 3 + x) = 9 + (x - 1) - 3x - ( - 5x - 3) = 8 + x - 3x + 5x + 3 = 8 + x 2x + 3 - 8 - x = 0 x - 5 = 0 x = 5.
Mejor respuesta
3
- 3x - ( - 6x - (3 - x)) = 9 + (x - 1) - 3x - ( - 6x - 3 + x) = 9 + (x - 1) - 3x - ( - 5x - 3) = 8 + x - 3x + 5x + 3 = 8 + x
2x + 3 - 8 - x = 0
x - 5 = 0
x = 5.
Otras 1 respuestas
Respuesta 2
- 3x - [ - 6x - (3 - x)] = 9 + (x - 1)
−3x−[−6x−(−x + 3)]−{9 + (x−1)} = 0
−3x−[−5x−3]−{9 + (x−1)} = 0
(2x + 3)−{9 + (x−1)} = 0
(2x + 3)−{x + 8} = 0
x−5 = 0
(1)⋅x + (−5) = 0
x = −(−5)1
x = 5.