2(x. 3x) = (x + 6)(3x + 40)?
2(x. 3x) = (x + 6)(3x + 40).
2(x. 3x) = (x + 6)(3x + 40).
En resumen
2x. 6x = (3x ^ 2) + 40x + 18x + 240 12x ^ 2 = (3x ^ 2) + 58x + 240 (12x ^ 2) - (3x ^ 2) = 58x + 240 9x ^ 2 - 58x - 240 = 0.
2x. 6x = (3x ^ 2) + 40x + 18x + 240
12x ^ 2 = (3x ^ 2) + 58x + 240
(12x ^ 2) - (3x ^ 2) = 58x + 240
9x ^ 2 - 58x - 240 = 0.