(2x + 3)³(x + 5y)³(10 + m)³(3p² + 1)³(n³ + 12)³?
(2x + 3)³ (x + 5y)³ (10 + m)³ (3p² + 1)³ (n³ + 12)³.
(2x + 3)³ (x + 5y)³ (10 + m)³ (3p² + 1)³ (n³ + 12)³.
Aplicamos productos notables :
(a + b)³ = a³ + 3a²b + 3ab² + b³
(2x + 3)³ = (2x)³ + 3(2x)² (3) + 3(2x)(3²) + 3³ =
8x³ + 9 (4x²) + 6x(9) + 27 = 8x³ + 36x² + 54x + 27
( x + 5y)³ = x³ + 3x²(5y) + 3x(5y)² + (5y)³ =
x³ + 15x²y + 3x(25y²) + 125y³ =
x³ + 15x²y + 75xy² + 125y³
(10 + m)³ = 10³ + 3(10)²m + 3(10)m² + m³ =
1000 + 3(100)m + 30m² + m³ =
1000 + 300m + 30m² + m³
(3p² + 1)³ = (3p²)³ + 3(3p²)² + 3 (3p²) + 1 =
27p⁶ + 3(9p⁴) + 9p² + 1 =
27p⁶ + 27p⁴ + 9p² + 1
(n³ + 12) = (n³)³ + 3 (n³)²(12) + 3(n³)(12)² + (12)³ =
n⁹ + 36n⁶ + 3n³(144) + 1728 =
n⁹ + 36n⁶ + 432n³ + 1728.
El. resultado es mn2p3(m2p + m3p2 + 6n3p + mn2).
(m + p) (m + p)→ m² + mp + mp + p²→ m² + 2mp + p².
5 / (5 + p - p) + p - (5 + p - 5) 5 / 5 + p - (p) 1 + 0 = 1.
Significa, yo quiero monda todos los ptos dias.
Amigo seria solo remplazar y operar.